## Appendix III. The Corner Boards

*The Tabernacle of Israel*, by George de Charms, 1969

Dr. E. E. Iungerich's solution (*Journal of Education, *Vol. 15, p. 143.)
It is a simple problem in mathematics: Let *x *and *y *be the two parts
into which the board is to be cut. Then:

x + y = 1^{1}/_{2} or ^{9}/_{6} cubits

x = ^{9}/_{6} - y

Since the board is ^{1}/_{6} cubit in thickness, then, if the
two legs are to be of equal length when placed together x = y - ^{1}/_{6
}. Substituting, we have

y _{ }*- *^{1}/_{6}*
= *^{9}/_{6 }*- *y

2y=^{5}/_{6}

x = ^{4}/_{6} or ^{2}/_{3}